14x^2-132x+160=0

Solution for 14x^2-132x+160=0 equation:

14x^2-132x+160=0

a = 14; b = -132; c = +160;
Δ = b2-4ac
Δ = -1322-4·14·160
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-132)-92}{2*14}=\frac{40}{28}
=1+3/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-132)+92}{2*14}=\frac{224}{28}
=8
$